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[bondsman]

Originally Posted by steel10

It seems like some are getting confused by my procedure. The last flush left 15.5 quarts of distilled water in the system when the pet**** quit draining. I then added 2 gallons (8 quarts) of pure Ford Gold Antifreeze.

8 quarts/15.5 quarts = 52% Antifreeze / 48% Water

I continued filling the coolant reservoir with a 50/50 mixture of Ford Gold Antifreeze and distilled water until the reservoir was full.

I checked my freeze protection using a coolant tester and it indicated that I was slightly over a 50/50 mix as was indicated by the freeze protection of ~-42deg F. A true 50/50 mix will yield a -34deg F freeze protection.

Cody

I think your reading with the coolant tester is correct. You will really never get all the antifreeze out of there... You calculations are not correct though.

50/50 is: half the capacity of the coolant system is water and the other half is straight antifreeze. Not 50% of the water left in the engine after you drain the radiator (thats where you got your 52/48 - 8 divided by 15.5). If you have 15.5qts of water and only 8qts of coolant you have 29.09% coolant in there (but there is still some old coolant in the "clear" water). It is essentially 50/50 of the 27.5 quarts not 50/50 of the 15.5 quarts.
Did you run the heat when you were heating it up? If not then you still had old coolant in your heater core.